SocialRetahd
Well-known member
who can help me with Linear Algebra and eigenvectors?
missquiet said:spanish oral![]()
Toad said:I'm not exactly sure what you mean by crossover point, but if it is just where the two curves intersect, the would it be possible to plot them to find where they intersect? Or set them equal to each other and solve for x...I'm guessing this isn't as simple as that. By the way, that second integral is possibly the nastiest one I have ever seen.
mienaino said:The crossover point is where the weight of a function with a lower initial value (f(0)) surpasses the weight of a function with a higher initial value (g(0)). So, in this case, the intersection of the second integrals.
I concur on the nasty bit. My teacher is somewhat sadistic. I asked her about it and she said the e^(-x^2) part is called the Hearth Function or something like that and that it can't be integrated (or at least, that is what I gleaned), but past a certain point, its integral can be approximated by integrating 1/x^2. I suppose I could try the graphing approach, provided my calculator or winplot can handle it, but the problem is not from a solve-by-graphing section, so I'm sure it's supposed to be solved exactly by non-graphic means. As for the second integral, I don't even know where to begin.
jauggy said:What do you study? What degree, major, year, etc.? I major in actuarial studies and finance for my Bachelor of Commerce Degree. Currently second year.
jauggy said:What do you study? What degree, major, year, etc.? I major in actuarial studies and finance for my Bachelor of Commerce Degree. Currently second year.